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IB Mathematics AA SL - Popular Quizzes

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Question 1

no calculator

easy

[Maximum mark: 7]

An arithmetic sequence is given by 33, 55, 7,7,\dots

  1. Write down the value of the common difference, dd. [1]

  2. Find

    1. u10u_{10};

    2. S10S_{10}. [4]

  3. Given that un=253u_n = 253, find the value of nn. [2]

easy

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Question 2

no calculator

easy

[Maximum mark: 6]

Let a=log5ba = \log_5b, where b>0b > 0. Write down each of the following expressions
in terms of aa.

  1. log5b4\log_5b^4 [2]

  2. log5(25b)\log_5 (25b) [2]

  3. log25b\log_{25}b [2]

easy

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Question 3

calculator

easy

[Maximum mark: 6]

Consider the expansion of (2x1)9(2x-1)^9.

  1. Write down the number of terms in this expansion. [1]

  2. Find the coefficient of the term in x2x^2. [5]

easy

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Question 4

no calculator

easy

[Maximum mark: 6]

In an arithmetic sequence, u4=12u_4 = 12, u11=9u_{11} = -9.

  1. Find the common difference. [2]

  2. Find the first term. [2]

  3. Find the sum of the first 1111 terms in the sequence. [2]

easy

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Question 5

calculator

easy

[Maximum mark: 5]

The third term, in descending powers of xx, in the expansion of (x+p)8(x+p)^8 is 252x6252x^6. Find the possible values of pp.

easy

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Question 6

no calculator

easy

[Maximum mark: 6]

  1. Show that (2n1)3+(2n+1)3=16n3+12n(2n-1)^3 + (2n+1)^3 = 16n^3+12n for nZn \in \mathbb{Z}. [3]

  2. Hence, or otherwise, prove that the sum of the cubes of any two consecutive odd integers is divisible by four. [3]

easy

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Question 7

no calculator

medium

[Maximum mark: 6]

  1. Write down the value of

    1. log28\log_2 8;

    2. log5(125)\log_5\Big(\dfrac{1}{25}\Big);

    3. log93\log_9 3. [3]

  2. Hence solve log28+log5(125)+log93=log16x\log_2 8 + \log_5\Big(\dfrac{1}{25}\Big) + \log_9 3 = \log_{16} x.[3]

medium

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Question 8

calculator

medium

[Maximum mark: 7]

The first three terms of a geometric sequence are u1=0.8u_1 = 0.8, u2=2.4u_2 = 2.4, u3=7.2u_3 = 7.2.

  1. Find the value of the common ratio, rr. [2]

  2. Find the value of S8S_8. [2]

  3. Find the least value of nn such that Sn>35000S_n > 35\hspace{0.15em}000. [3]

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Question 9

calculator

medium

[Maximum mark: 6]

On 11st of January 20222022, Grace invests $P\$P in an account that pays a nominal annual interest rate of 66 %, compounded quarterly.

The amount of money in Grace's account at the end of each year follows a geometric sequence with common ratio, α\alpha.

  1. Find the value of α\alpha, giving your answer to four significant figures. [3]

Grace makes no further deposits or withdrawals from the account.

  1. Find the year in which the amount of money in Grace's account will become triple the amount she invested. [3]

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Question 10

calculator

medium

[Maximum mark: 6]

Jack rides his bike to work each morning. During the first minute, he travels 160160 metres. In each subsequent minute, he travels 8080 % of the distance travelled during the previous minute.

The distance from his home to work is 750750 metres. Jack leaves his house at 88:3030 am and must be at work at 88:4040 am.

Will Jack arrive to work on time? Justify your answer.

medium

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Question 11

no calculator

medium

[Maximum mark: 5]

Find the values of xx when 25x22x=(1125)4x+225^{x^2-2x} = \left(\dfrac{1}{125}\right)^{4x+2}.

medium

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Question 12

no calculator

medium

[Maximum mark: 5]

The third term of an arithmetic sequence is equal to 77 and the sum of the first 88 terms is 2020.

Find the common difference and the first term.

medium

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Question 13

calculator

medium

[Maximum mark: 6]

The sum of the first three terms of a geometric sequence is 81.381.3, and the sum of the infinite sequence is 300300. Find the common ratio.

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Question 14

calculator

medium

[Maximum mark: 6]

Consider the expansion of (x3+2x)8\bigg(x^3+\dfrac{2}{x}\bigg)^8.

  1. Write down the number of terms in this expansion. [1]

  2. Find the coefficient of the term in x4x^4. [5]

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Question 15

no calculator

hard

[Maximum mark: 6]

The 11st, 55th and 1313th terms of an arithmetic sequence, with common difference dd, d0d \neq 0, are the first three terms of a geometric sequence, with common ratio rr, r1r \neq 1. Given that the 11st term of both sequences is 1212, find the value of dd and the value of rr.

hard

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Question 16

calculator

hard

[Maximum mark: 6]

Consider the expansion of (3x+px)8\bigg(3x + \dfrac{p}{x}\bigg)^8, where p>0p > 0. The coefficient of the term

in x4x^4 is equal to the coefficient of the term in x6x^6. Find pp.

hard

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Question 17

calculator

hard

[Maximum mark: 8]

It is known that the number of trees in a small forest will decrease by 55 % each year unless some new trees are planted. At the end of each year, 600600 new trees are planted to the forest. At the start of 20212021, there are 82008200 trees in the forest.

  1. Show that there will be roughly 90609060 trees in the forest at the start of 20262026. [4]

  2. Find the approximate number of trees in the forest at the start of 20412041. [4]

hard

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Question 18

no calculator

hard

[Maximum mark: 14]

The first two terms of an infinite geometric sequence, in order, are

3log3x,2log3x,where x>0.3\log_3x,\,\, 2\log_3x,\,\, \text{where $x > 0$.}
  1. Find the common ratio, rr. [2]

  2. Show that the sum of the infinite sequence is 9log3x9\log_3 x. [3]

The first three terms of an arithmetic sequence, in order, are

log3x,log3x3,log3x9,where x>0.\log_3x,\,\, \log_3 \dfrac{x}{3},\,\, \log_3\dfrac{x}{9},\,\, \text{where $x > 0$.}
  1. Find the common difference dd, giving your answer as an integer. [3]

Let S6S_6 be the sum of the first 66 terms of the arithmetic sequence.

  1. Show that S6=6log3x15S_6 = 6\log_3 x - 15. [3]

  2. Given that S6S_6 is equal to one third of the sum of the infinite geometric
    sequence, find xx, giving your answer in the form apa^p where a,pZa,p \in \mathbb{Z}. [3]

hard

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Question 19

no calculator

hard

[Maximum mark: 15]

The first three terms of an infinite geometric sequence are k4,4,k+2k-4,\,\, 4,\,\, k+2, where kZk \in \mathbb{Z}.

    1. Write down an expression for the common ratio, rr.

    2. Hence show that kk satisfies the equation k22k24=0k^2 - 2k - 24 = 0.[5]

    1. Find the possible values for kk.

    2. Find the possible values for rr. [5]

  1. The geometric sequence has an infinite sum.

    1. Which value of rr leads to this sum. Justify your answer.

    2. Find the sum of the sequence. [5]

hard

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Question 20

calculator

hard

[Maximum mark: 7]

Given that (5+nx)2(1+35x)n=25+100x+(5+nx)^2\bigg(1+\dfrac{3}{5}x\bigg)^n\hspace{-0.25em}=\hspace{0.05em}25+100x+\cdots, find the value of nn.

hard

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