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IB Mathematics AA SL - Questionbank

Topic 1 All - Number & Algebra

All Questions for Topic 1 (Number & Algebra). Sequences & Series, Exponents & Logs, Binomial Theorem, Proofs

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Paper 2

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Question 1

no calculator

easy

[Maximum mark: 4]

Expand (2x+1)4(2x + 1)^4 in descending powers of xx and simplify your answer.

easy

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Question 2

calculator

easy

[Maximum mark: 6]

An arithmetic sequence has u1=40u_1= 40, u2=32u_2 = 32, u3=24u_3 = 24.

  1. Find the common difference, dd. [2]

  2. Find u8u_8. [2]

  3. Find S8S_8. [2]

easy

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Question 3

no calculator

easy

[Maximum mark: 7]

Find the value of each of the following, giving your answer as an integer.

  1. log10100\log_{10} 100. [2]

  2. log1050+log102\log_{10} 50 + \log_{10} 2. [2]

  3. log104log1040\log_{10} 4 - \log_{10} 40. [3]

easy

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Question 4

no calculator

easy

[Maximum mark: 6]

Find the value of each of the following, giving your answer as an integer.

  1. log66\log_6 6. [2]

  2. log69+log64\log_6 9 + \log_6 4. [2]

  3. log672log62\log_6 72 - \log_6 2. [2]

easy

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Question 5

no calculator

easy

[Maximum mark: 6]

Consider an arithmetic sequence 2,6,10,14,2,6,10,14,\dots

  1. Find the common difference, dd. [2]

  2. Find the 1010th term in the sequence. [2]

  3. Find the sum of the first 1010 terms in the sequence. [2]

easy

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Question 6

calculator

easy

[Maximum mark: 6]

Only one of the following four sequences is arithmetic and only one of them is geometric.

an=13,14,15,16,cn=3,1,13,19,bn=2.5,5,7.5,10,dn=1,3,6,10,\begin{array}{rcccccl} a_n &=& \dfrac{1}{3},\,\dfrac{1}{4},\,\dfrac{1}{5},\,\dfrac{1}{6},\,\dots &\,\hspace{4em}\,& c_n &=& 3,\,1,\,\dfrac{1}{3},\,\dfrac{1}{9},\,\dots \\[12pt] b_n &=& 2.5,\,5,\,7.5,\,10,\,\dots &\,\hspace{4em}\,& d_n &=& 1,\,3,\,6,\,10,\,\dots \end{array}
  1. State which sequence is arithmetic and find the common difference of the sequence. [2]

  2. State which sequence is geometric and find the common ratio of the sequence.[2]

  3. For the geometric sequence find the exact value of the sixth term. Give your answer as a fraction. [2]

easy

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Question 7

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easy

[Maximum mark: 6]

Consider the infinite geometric sequence 44804480, 3360-3360, 25202520, 1890,-1890,\dots

  1. Find the common ratio, rr. [2]

  2. Find the 2020th term. [2]

  3. Find the exact sum of the infinite sequence. [2]

easy

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Question 8

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easy

[Maximum mark: 4]

Expand (2x3)4(2x - 3)^4 in descending powers of xx and simplify your answer.

easy

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Question 9

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easy

[Maximum mark: 4]

Prove that the sum of three consecutive positive integers is divisible by 33.

easy

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Question 10

calculator

easy

[Maximum mark: 6]

Only one of the following four sequences is arithmetic and only one of them is geometric.

an=1,5,10,15,cn=1.5,3,4.5,6,bn=12,23,34,45,dn=2,1,12,14,\begin{array}{rcccccl} a_n &=& 1,\,5,\,10,\,15,\,\dots &\,\hspace{4em}\,& c_n &=& 1.5,\,3,\,4.5,\,6,\,\dots \\[12pt] b_n &=& \dfrac{1}{2},\,\dfrac{2}{3},\,\dfrac{3}{4},\,\dfrac{4}{5},\,\dots &\,\hspace{4em}\,& d_n &=& 2,\,1,\,\dfrac{1}{2},\,\dfrac{1}{4},\,\dots \end{array}
  1. State which sequence is arithmetic and find the common difference of the sequence. [2]

  2. State which sequence is geometric and find the common ratio of the sequence.[2]

  3. For the geometric sequence find the exact value of the eighth term. Give your answer as a fraction. [2]

easy

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Question 11

no calculator

easy

[Maximum mark: 4]

Consider two consecutive positive integers, kk and k+1k+1.

Show that the difference of their squares is equal to the sum of the two integers.

easy

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Question 12

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easy

[Maximum mark: 6]

The table shows the first four terms of three sequences: unu_n, vnv_n, and wnw_n.

c39694c1cf7513ffce115791e6b0f1c54c230963.svg

  1. State which sequence is

    1. arithmetic;

    2. geometric. [2]

  2. Find the sum of the first 5050 terms of the arithmetic sequence. [2]

  3. Find the exact value of the 1313th term of the geometric sequence. [2]

easy

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Question 13

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easy

[Maximum mark: 4]

The product of three consecutive integers is increased by the middle integer.

Prove that the result is a perfect cube.

easy

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Question 14

calculator

easy

[Maximum mark: 6]

Consider the expansion of (2x1)9(2x-1)^9.

  1. Write down the number of terms in this expansion. [1]

  2. Find the coefficient of the term in x2x^2. [5]

easy

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Question 15

calculator

easy

[Maximum mark: 6]

Jeremy invests $8000\$8000 into a savings account that pays an annual interest rate of 5.55.5 %, compounded annually.

  1. Write down a formula which calculates that total value of the investment after nn years. [2]

  2. Calculate the amount of money in the savings account after:

    1. 11 year;

    2. 33 years. [2]

  3. Jeremy wants to use the money to put down a $10000\$10\hspace{0.15em}000 deposit on an apartment. Determine if Jeremy will be able to do this within a 55-year timeframe.[2]

easy

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Question 16

calculator

easy

[Maximum mark: 5]

Consider the expansion of (x3)8(x-3)^8.

  1. Write down the number of terms in this expansion. [1]

  2. Find the coefficient of the term in x6x^6. [4]

easy

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Question 17

calculator

easy

[Maximum mark: 6]

Consider the infinite geometric sequence 90009000, 7200-7200, 57605760, 4608-4608, ...

  1. Find the common ratio. [2]

  2. Find the 2525th term. [2]

  3. Find the exact sum of the infinite sequence. [2]

easy

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Question 18

no calculator

easy

[Maximum mark: 6]

Let log2a=p\log_2 a = p, log2b=q\log_2 b = q, log2c=r\log_2 c = r. Write down the following expressions in terms of pp, qq and rr.

  1. log2(abc)\log_2\Big(\dfrac{ab}{c}\Big) [2]

  2. log2(a2cb3)\log_2\Big(\dfrac{a^2c}{b^3}\Big) [2]

  3. logab\log_a b [2]

easy

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Question 19

no calculator

easy

[Maximum mark: 7]

An arithmetic sequence is given by 33, 55, 7,7,\dots

  1. Write down the value of the common difference, dd. [1]

  2. Find

    1. u10u_{10};

    2. S10S_{10}. [4]

  3. Given that un=253u_n = 253, find the value of nn. [2]

easy

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Question 20

no calculator

easy

[Maximum mark: 7]

Let p=ln2p=\ln 2 and q=ln6q = \ln 6. Write down the following expressions in terms of pp and qq.

  1. ln12\ln 12 [2]

  2. ln3\ln 3 [2]

  3. ln48\ln 48 [3]

easy

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Question 21

no calculator

easy

[Maximum mark: 6]

Consider the following sequence of figures.

AA008

Figure 1 contains 66 line segments.

  1. Given that Figure nn contains 101101 line segments, show that n=20n = 20.[3]

  2. Find the total number of line segments in the first 2020 figures. [3]

easy

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Question 22

calculator

easy

[Maximum mark: 6]

Hannah buys a car for $24900\$24\hspace{0.15em}900. The value of the car depreciates by 1616 % each year.

  1. Find the value of the car after 1010 years. [3]

Patrick buys a car for $12000\$12\hspace{0.15em}000. The car depreciates by a fixed percentage each year, and after 66 years it is worth $6200\$6200.

  1. Find the annual rate of depreciation of the car. [3]

easy

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Question 23

calculator

easy

[Maximum mark: 6]

A 33D printer builds a set of 4949 Eif\text{f}fel Tower Replicas in different sizes. The height of the largest tower in this set is 6464 cm. The heights of successive smaller towers are 9595 % of the preceding larger tower, as shown in the diagram below.

AA724a

  1. Find the height of the smallest tower in this set. [3]

  2. Find the total height if all 4949 towers were placed one on top of another. [3]

easy

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Question 24

no calculator

easy

[Maximum mark: 6]

Let a=log5ba = \log_5b, where b>0b > 0. Write down each of the following expressions
in terms of aa.

  1. log5b4\log_5b^4 [2]

  2. log5(25b)\log_5 (25b) [2]

  3. log25b\log_{25}b [2]

easy

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Question 25

calculator

easy

[Maximum mark: 6]

Julia wants to buy a house that requires a deposit of 7400074\hspace{0.15em}000 Australian dollars (AUD).

Julia is going to invest an amount of AUD in an account that pays a nominal annual interest rate of 5.55.5 %, compounded monthly.

  1. Find the amount of AUD Julia needs to invest to reach 7400074\hspace{0.15em}000 AUD after 88 years. Give your answer correct to the nearest dollar. [3]

Julia's parents offer to add 50005000 AUD to her initial investment from part (a), however, only if she invests her money in a more reliable bank that pays a nominal annual interest rate only of 3.53.5 %, compounded quarterly.

  1. Find the number of years it would take Julia to save the 7400074\hspace{0.15em}000 AUD if she accepts her parents money and follows their advice. Give your answer correct to the nearest year. [3]

easy

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Question 26

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easy

[Maximum mark: 6]

The fifth term, u5u_5, of a geometric sequence is 125125. The sixth term, u6u_6, is 156.25156.25.

  1. Find the common ratio of the sequence. [2]

  2. Find u1u_1, the first term of the sequence. [2]

  3. Calculate the sum of the first 1212 terms of the sequence. [2]

easy

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Question 27

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easy

[Maximum mark: 6]

In an arithmetic sequence, u5=24u_5 = 24, u13=80u_{13} = 80.

  1. Find the common difference. [2]

  2. Find the first term. [2]

  3. Find the sum of the first 2020 terms in the sequence. [2]

easy

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Question 28

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easy

[Maximum mark: 6]

In this question give all answers correct to two decimal places.

Mia deposits 40004000 Australian dollars (AUD) into a bank account. The bank pays a nominal annual interest rate of 66 %, compounded semi-annually.

  1. Find the amount of interest that Mia will earn over the next 2.52.5 years. [3]

Ella also deposits AUD into a bank account. Her bank pays a nominal annual interest\text{interest} rate of 44 %, compounded monthly. In 2.52.5 years, the total amount in Ella's account will be 40004000 AUD.

  1. Find the amount that Ella deposits in the bank account. [3]

easy

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Question 29

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easy

[Maximum mark: 5]

Maria invests $25000\$25\hspace{0.15em}000 into a savings account that pays a nominal annual interest rate of 4.254.25%, compounded monthly.

  1. Calculate the amount of money in the savings account after 33 years. [2]

  2. Calculate the number of years it takes for the account to reach $40000\$40\hspace{0.15em}000. [3]

easy

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Question 30

no calculator

easy

[Maximum mark: 6]

The first three terms of a geometric sequence are u1=32u_1 = 32, u2=16u_2 = -16, u3=8u_3 = 8.

  1. Find the value of the common ratio, rr. [2]

  2. Find u6u_6. [2]

  3. Find SS_{\infty}. [2]

easy

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Question 31

no calculator

easy

[Maximum mark: 6]

In an arithmetic sequence, u4=12u_4 = 12, u11=9u_{11} = -9.

  1. Find the common difference. [2]

  2. Find the first term. [2]

  3. Find the sum of the first 1111 terms in the sequence. [2]

easy

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Question 32

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easy

[Maximum mark: 6]

Emily deposits 20002000 Australian dollars (AUD) into a bank account. The bank pays a nominal annual interest rate of 44 %, compounded monthly.

  1. Find the amount of money that Emily will have in her bank account after 55 years. Give your answer correct to two decimal places. [3]

Emily will withdraw the money back from her bank account when the amount reaches 30003000 AUD.

  1. Find the time, in months, until Emily withdraws the money from her bank account. [3]

easy

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Question 33

no calculator

easy

[Maximum mark: 6]

  1. Show that (2n1)3+(2n+1)3=16n3+12n(2n-1)^3 + (2n+1)^3 = 16n^3+12n for nZn \in \mathbb{Z}. [3]

  2. Hence, or otherwise, prove that the sum of the cubes of any two consecutive odd integers is divisible by four. [3]

easy

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Question 34

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easy

[Maximum mark: 6]

A tennis ball bounces on the ground nn times. The heights of the bounces, h1,h2,h3,,hn,h_1, h_2, h_3, \dots,h_n, form a geometric sequence. The height that the ball bounces the first time, h1h_1, is 8080 cm, and the second time, h2h_2, is 6060 cm.

  1. Find the value of the common ratio for the sequence. [2]

  2. Find the height that the ball bounces the tenth time, h10h_{10}. [2]

  3. Find the total distance travelled by the ball during the first six bounces (up and down). Give your answer correct to 22 decimal places. [2]

easy

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Question 35

calculator

easy

[Maximum mark: 5]

In an arithmetic sequence, the sum of the 2nd and 6th term is 3232.
Given that the sum of the first six terms is 120120, determine the first term and common difference of the sequence.

easy

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Question 36

calculator

easy

[Maximum mark: 6]

Ali bought a car for $18000\$18\hspace{0.15em}000. The value of the car depreciates by 10.510.5 % each year.

  1. Find the value of the car at the end of the first year. [2]

  2. Find the value of the car after 44 years. [2]

  3. Calculate the number of years it will take for the car to be worth exactly half its original value. [2]

easy

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Question 37

no calculator

easy

[Maximum mark: 5]

  1. Prove that 5x2=5x(x2)10x2(x2)\dfrac{5}{x^2} = \dfrac{5}{x(x-2)}-\dfrac{10}{x^2(x-2)}. [3]

  2. Determine the set of numbers xx for which the proof in part (a) is valid. [2]

easy

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Question 38

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easy

[Maximum mark: 6]

The fourth term, u4u_4, of a geometric sequence is 135135. The fifth term, u5u_5, is 8181.

  1. Find the common ratio of the sequence. [2]

  2. Find u1u_1, the first term of the sequence. [2]

  3. Calculate the sum of the first 2020 terms of the sequence. [2]

easy

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Question 39

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easy

[Maximum mark: 5]

An arithmetic sequence has first term 4545 and common difference 1.5-1.5.

  1. Given that the kkth term of the sequence is zero, find the value of kk. [2]

Let SnS_n denote the sum of the first nn terms of the sequence.

  1. Find the maximum value of SnS_n. [3]

easy

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Question 40

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easy

[Maximum mark: 6]

The fifth term, u5u_5, of an arithmetic sequence is 2525. The eleventh term, u11u_{11}, of the same sequence is 4949.

  1. Find dd, the common difference of the sequence. [2]

  2. Find u1u_1, the first term of the sequence. [2]

  3. Find S100S_{100}, the sum of the first 100100 terms of the sequence. [2]

easy

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Question 41

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easy

[Maximum mark: 6]

The third term, u3u_3, of an arithmetic sequence is 77. The common difference of
the sequence, dd, is 33.

  1. Find u1u_1, the first term of the sequence. [2]

  2. Find u60u_{60}, the 6060th term of sequence. [2]

The first and fourth terms of this arithmetic sequence are the first two terms
of a geometric sequence.

  1. Calculate the sixth term of the geometric sequence. [2]

easy

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Question 42

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easy

[Maximum mark: 5]

The third term, in descending powers of xx, in the expansion of (x+p)8(x+p)^8 is 252x6252x^6. Find the possible values of pp.

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Question 43

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easy

[Maximum mark: 6]

Greg has saved 20002000 British pounds (GBP) over the last six months. He decided to deposit his savings in a bank which offers a nominal annual interest rate of 8%\text{\(8\)\hspace{0.05em}\%}, compounded monthly, for two years.

  1. Calculate the total amount of interest Greg would earn over the two years. Give your answer correct to two decimal places. [3]

Greg would earn the same amount of interest, compounded semi-annually, for two years if he deposits his savings in a second bank.

  1. Calculate the nominal annual interest rate the second bank offers. [3]

easy

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Question 44

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medium

[Maximum mark: 6]

On 11st of January 20212021, Fiona decides to take out a bank loan to purchase a new Tesla electric car. Fiona takes out a loan of $P\$P with a bank that offers a nominal annual interest rate of 2.6%2.6\hspace{0.05em}\%, compounded monthly.

The size of Fiona's loan at the end of each year follows a geometric sequence with common ratio, α\alpha.

  1. Find the value of α\alpha, giving your answer to five significant figures. [3]

The bank lets the size of Fiona's loan increase until it becomes triple the size of the original loan. Once this happens, the bank demands that Fiona pays the entire amount back to close the loan.

  1. Find the year during which Fiona will need to pay back the loan. [3]

medium

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Question 45

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medium

[Maximum mark: 6]

The first term of an arithmetic sequence is 2424 and the common difference is 1616.

  1. Find the value of the 6262nd term of the sequence. [2]

The first term of a geometric sequence is 88. The 44th term of the geometric sequence is equal to the 1313th term of the arithmetic sequence given above.

  1. Write down an equation using this information. [2]

  2. Calculate the common ratio of the geometric sequence. [2]

medium

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Question 46

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[Maximum mark: 6]

The Australian Koala Foundation estimates that there are about 4500045\hspace{0.15em}000 koalas left in the wild in 20192019. A year before, in 20182018, the population of koalas was estimated as 5000050\hspace{0.15em}000. Assuming the population of koalas continues to decrease by the same percentage each year, find:

  1. the exact population of koalas in 20222022; [3]

  2. the number of years it will take for the koala population to reduce to half of its number in 20182018. [3]

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Question 47

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[Maximum mark: 5]

Consider a=log6364×log6263×log6162××log23a = \log_{63}64\times\log_{62}63\times\log_{61}62\times\dots\times\log_{2}3. Given that aZa\in\mathbb{Z}, find the value of aa.

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Question 48

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[Maximum mark: 6]

Landmarks are placed along the road from London to Edinburgh and the distance between each landmark is 16.116.1 km. The first landmark placed on the road is 124.7124.7 km from London, and the last landmark is near Edinburgh. The length of the road from London to Edinburgh is 667.1667.1 km.

  1. Find the distance between the fifth landmark and London. [3]

  2. Determine how many landmarks there are along the road. [3]

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Question 49

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[Maximum mark: 6]

  1. Write the expression 4ln2ln84\ln 2 - \ln 8 in the form of lnk\ln k, where kZk \in \mathbb{Z}. [3]

  2. Hence, or otherwise, solve 4ln2ln8=ln(2x)4\ln 2 - \ln 8 = -\ln (2x). [3]

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Question 50

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[Maximum mark: 5]

Solve the equation log5xlog54=2+log53\log_5 x - \log_5 4 = 2 + \log_5 3 for xx.

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Question 51

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[Maximum mark: 6]

On Gary's 5050th birthday, he invests $P\$P in an account that pays a nominal annual interest rate of 55 %, compounded monthly.

The amount of money in Gary's account at the end of each year follows a geometric sequence with common ratio, α\alpha.

  1. Find the value of α\alpha, giving your answer to four significant figures. [3]

Gary makes no further deposits or withdrawals from the account.

  1. Find the age Gary will be when the amount of money in his account will be double the amount he invested. [3]

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Question 52

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[Maximum mark: 6]

Given that loga2=5\log_a 2 = 5.

  1. Find the exact value of loga32\log_a 32. [2]

  2. Find the exact value of loga2\log_{\sqrt{a}} 2. [2]

  3. Find the value of aa, giving your answer correct to 33 significant figures. [2]

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Question 53

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[Maximum mark: 5]

Find the values of xx when 27x+2=(19)2x+427^{x+2} = \left(\dfrac{1}{9}\right)^{2x+4}.

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Question 54

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[Maximum mark: 5]

Solve the equation log3xlog35=1+log34\log_3 x - \log_3 5 = 1 + \log_3 4 for xx.

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Question 55

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[Maximum mark: 6]

  1. Write down the value of

    1. log28\log_2 8;

    2. log5(125)\log_5\Big(\dfrac{1}{25}\Big);

    3. log93\log_9 3. [3]

  2. Hence solve log28+log5(125)+log93=log16x\log_2 8 + \log_5\Big(\dfrac{1}{25}\Big) + \log_9 3 = \log_{16} x.[3]

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Question 56

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[Maximum mark: 6]

  1. Write down the value of

    1. log381\log_3 81;

    2. log2(18)\log_2\Big(\dfrac{1}{8}\Big);

    3. log255\log_{25} 5. [3]

  2. Hence solve log381+log2(18)+log255=log9x\log_3 81 + \log_2\Big(\dfrac{1}{8}\Big) + \log_{25} 5 = \log_{9} x.[3]

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Question 57

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[Maximum mark: 5]

Consider the expansion of (x22+ax)6\left(\dfrac{x^2}{2} + \dfrac{a}{x}\right)^6. The constant term is 960960.

Find the possible values of aa.

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Question 58

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[Maximum mark: 6]

Given that logb3=10\log_b 3 = 10.

  1. Find the exact value of logb81\log_b 81. [2]

  2. Find the exact value of logb23\log_{b^2} 3. [2]

  3. Find the value of bb, giving your answer correct to 33 significant figures. [2]

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Question 59

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[Maximum mark: 6]

The fourth term of an arithmetic sequence is equal to 1313 and the sum of the first 1010 terms is 5555.

  1. Find the common difference and the first term. [4]

  2. Determine the greatest value of nn such that the nnth term is positive. [2]

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Question 60

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[Maximum mark: 7]

The first three terms of a geometric sequence are u1=0.4u_1 = 0.4, u2=0.6u_2 = 0.6, u3=0.9u_3 = 0.9.

  1. Find the value of the common ratio, rr. [2]

  2. Find the sum of the first ten terms in the sequence. [2]

  3. Find the greatest value of nn such that Sn<650S_n < 650. [3]

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Question 61

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[Maximum mark: 6]

In this question give all answers correct to the nearest whole number.

A population of goats on an island starts at 232232. The population is expected to increase by 1515 % each year.

  1. Find the expected population size after:

    1. 1010 years;

    2. 2020 years. [4]

  2. Find the number of years it will take for the population to reach 1500015\hspace{0.15em}000. [2]

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Question 62

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[Maximum mark: 5]

Find the values of xx when 25x22x=(1125)4x+225^{x^2-2x} = \left(\dfrac{1}{125}\right)^{4x+2}.

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Question 63

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[Maximum mark: 6]

On 11st of January 20222022, Grace invests $P\$P in an account that pays a nominal annual interest rate of 66 %, compounded quarterly.

The amount of money in Grace's account at the end of each year follows a geometric sequence with common ratio, α\alpha.

  1. Find the value of α\alpha, giving your answer to four significant figures. [3]

Grace makes no further deposits or withdrawals from the account.

  1. Find the year in which the amount of money in Grace's account will become triple the amount she invested. [3]

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Question 64

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[Maximum mark: 6]

Jack rides his bike to work each morning. During the first minute, he travels 160160 metres. In each subsequent minute, he travels 8080 % of the distance travelled during the previous minute.

The distance from his home to work is 750750 metres. Jack leaves his house at 88:3030 am and must be at work at 88:4040 am.

Will Jack arrive to work on time? Justify your answer.

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Question 65

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[Maximum mark: 7]

In an arithmetic sequence, the third term is 4141 and the ninth term is 2323.

  1. Find the common difference. [2]

  2. Find the first term. [2]

  3. Find the smallest value of nn such that Sn<0S_n < 0. [3]

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Question 66

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[Maximum mark: 5]

Solve the equation log3(x24x+4)=1+log3(x2)\log_3(x^2-4x+4) = 1 + \log_3(x-2).

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Question 67

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[Maximum mark: 5]

Solve the equation log2(x22x+1)=1+log2(x1)\log_2(x^2-2x+1) = 1 + \log_2(x-1).

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Question 68

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[Maximum mark: 6]

The sum of the first three terms of a geometric sequence is 92.592.5, and the sum of the infinite sequence is 160160. Find the common ratio.

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Question 69

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[Maximum mark: 7]

The first three terms of a geometric sequence are u1=0.8u_1 = 0.8, u2=2.4u_2 = 2.4, u3=7.2u_3 = 7.2.

  1. Find the value of the common ratio, rr. [2]

  2. Find the value of S8S_8. [2]

  3. Find the least value of nn such that Sn>35000S_n > 35\hspace{0.15em}000. [3]

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Question 70

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[Maximum mark: 6]

Sarah walks to school each morning. During the first minute, she travels 130130 metres\text{metres}. In each subsequent minute, she travels 55 metres less than the distance she travelled during the previous minute. The distance from her home to school is 950950 metres. Sarah leaves her house at 88:0000 am and must be at school by 88:1010 am.

Will Sarah arrive to school on time? Justify your answer.

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Question 71

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[Maximum mark: 5]

Solve log6(x)+log6(x5)=2\log_6(x) + \log_6(x-5) = 2, for x>5x > 5.

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Question 72

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[Maximum mark: 7]

In a geometric sequence, u2=6u_2 = 6, u5=20.25u_5 = 20.25.

  1. Find the common ratio, rr. [2]

  2. Find u1u_1. [2]

  3. Find the greatest value of nn such that un<200u_n < 200. [3]

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Question 73

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[Maximum mark: 6]

Peter is playing on a swing during a school lunch break. The height of the first swing was 22 m and every subsequent swing was 8484 % of the previous one. Peter's friend, Ronald, gives him a push whenever the height falls below 11 m.

  1. Find the height of the third swing. [2]

  2. Find the number of swings before Ronald gives Peter a push. [2]

  3. Calculate the total height of swings if Peter is left to swing until coming
    to rest. [2]

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Question 74

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[Maximum mark: 6]

Consider the expansion of (x+a)7bx\dfrac{(x+a)^7}{bx}, where a>0a > 0. The coefficient of the term in x5x^5 is 22, and the coefficient of the term in x3x^3 is 16901690.

Find the value of aa and the value of bb.

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Question 75

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[Maximum mark: 6]

The sum of an infinite geometric sequence is 2727. The second term of the sequence is 66. Find the possible values of rr.

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Question 76

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[Maximum mark: 6]

Let un=5n1u_n = 5n-1, for nZ+n \in \mathbb{Z}^+.

    1. Using sigma notation, write down an expression for u1+u2+u3++u10u_1 + u_2 + u_3 + \dots + u_{10}.

    2. Find the value of the sum from part (a) (i). [4]

A geometric sequence is defined by vn=5×2n1v_n = 5\times 2^{n-1}, for nZ+n \in \mathbb{Z}^+.

  1. Find the value of the sum of the geometric series k=16vk\displaystyle \sum_{k = 1}^6 \hspace{0.1em}v_k.[2]

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Question 77

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medium

[Maximum mark: 6]

Find the value of

  1. log575log53\log_5 75 - \log_5 3; [2]

  2. 25log5825^{\log_5 8}. [4]

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Question 78

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[Maximum mark: 6]

The sum of the first three terms of a geometric sequence is 81.381.3, and the sum of the infinite sequence is 300300. Find the common ratio.

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Question 79

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[Maximum mark: 6]

The first term and the common ratio of a geometric series are denoted, respectively, by u1u_1 and rr, where u1,rQu_1,r \in \mathbb{Q}. Given that the fourth term is 6464 and the sum to infinity is 625625, find the value of u1u_1 and the value of rr.

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Question 80

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[Maximum mark: 6]

The seventh term of an arithmetic sequence is equal to 11 and the sum of the first 1616 terms is 5252.

Find the common difference and the first term.

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Question 81

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medium

[Maximum mark: 6]

Find the value of

  1. log798log72\log_7 98 - \log_7 2; [2]

  2. 49log7649^{\log_7 6}. [4]

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Question 82

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[Maximum mark: 6]

Consider the sum S=k=4l(2k3)\displaystyle S = \sum_{k = 4}^l (2k-3), where ll is a positive integer greater than 44.

  1. Write down the first three terms of the series. [2]

  2. Write down the number of terms in the series. [1]

  3. Given that S=725S = 725, find the value of ll. [3]

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Question 83

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[Maximum mark: 5]

The third term of an arithmetic sequence is equal to 77 and the sum of the first 88 terms is 2020.

Find the common difference and the first term.

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Question 84

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[Maximum mark: 6]

Consider the expansion of (x3+2x)8\bigg(x^3+\dfrac{2}{x}\bigg)^8.

  1. Write down the number of terms in this expansion. [1]

  2. Find the coefficient of the term in x4x^4. [5]

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Question 85

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[Maximum mark: 15]

The equation e2x12ex=32e^{2x} - 12e^x = -32 has two solutions, x1x_1 and x2x_2.

  1. Find the value of x1x_1 and the value of x2x_2.[5]

A second equation, 2(log9x)(log3x)6log9x2log3x=62\left(\log_{\,9}x\right)\left(\log_{\,3}x\right) - 6\log_{\,9}x - 2\log_{\,3}x = -6, also has two solutions, x3x_3 and x4x_4.

    1. Show that this second equation can be expressed as

      (log3x)25log3x+6=0\begin{align*} \left(\log_{\,3}x\right)^2 -5\log_{\,3}x + 6 = 0 \end{align*}
    2. Hence find the value of x3x_3 and the value of x4x_4. [7]

  1. Given that x1+x2=a(x3+x4)x_1 + x_2 = a(x_3 + x_4), find the value of aa. Give your answer in the form blncb\ln c, where b,cRb,c \in \mathbb{R}.[3]

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Question 86

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[Maximum mark: 6]

In the expansion of px2(5+px)8px^2(5 + px)^8, the coefficient of the term in x6x^6 is 34023402. Find the value of pp.

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Question 87

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[Maximum mark: 5]

Consider a geometric sequence with common ratio rr such that 0<r<10 < r < 1.

  1. Show that unun+1=un(1r)u_n - u_{n+1} = u_n(1-r).[2]

A geometric sequence has a first term of 150 and a second term of 120.

  1. Find the smallest value of nn such that unun+1<1u_n - u_{n+1} < 1.[3]

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Question 88

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medium

[Maximum mark: 18]

The first three terms of an infinite sequence, in order, are

2lnx,qlnx,lnx where  x>0.2\ln x,\,\, q\ln x,\,\, \ln \sqrt{x}\,\,\, \text{ where $\ x > 0$.}

First consider the case in which the series is geometric.

    1. Find the possible values of qq.

    2. Hence or otherwise, show that the series is convergent. [3]

  1. Given that q>0q>0 and S=8ln3S_\infty=8\ln{3}, find the value of xx. [3]

Now suppose that the series is arithmetic.

    1. Show that q=54q=\dfrac{5}{4}.

    2. Write down the common difference in the form mlnxm\ln x, where mQm \in \mathbb{Q}. [4]

  1. Given that the sum of the first nn terms of the sequence is lnx5\ln \sqrt{x^5}, find the value of nn. [8]

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Question 89

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[Maximum mark: 6]

Consider the expansion of (3x+px)8\bigg(3x + \dfrac{p}{x}\bigg)^8, where p>0p > 0. The coefficient of the term

in x4x^4 is equal to the coefficient of the term in x6x^6. Find pp.

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Question 90

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hard

[Maximum mark: 6]

The 11st, 55th and 1313th terms of an arithmetic sequence, with common difference dd, d0d \neq 0, are the first three terms of a geometric sequence, with common ratio rr, r1r \neq 1. Given that the 11st term of both sequences is 1212, find the value of dd and the value of rr.

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Question 91

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[Maximum mark: 7]

Let f(x)=(x2+a)5f(x) = (x^2 + a)^5.

In the expansion of the derivative, f(x)f'(x), the coefficient of the term in x5x^5 is 960960. Find the possible values of aa.

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Question 92

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hard

[Maximum mark: 5]

Solve the equation 9x+23x+1=19^x + 2\cdot3^{x+1} = 1.

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Question 93

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hard

[Maximum mark: 7]

Solve the simultaneous equations:

1+2log5x=log57ylog7(6x1)=1+log7y\begin{aligned} 1 + 2\log_5 x &= \log_5 7y \\[6pt] \log_7 (6x-1) &= 1 + \log_7 y\end{aligned}

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Question 94

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[Maximum mark: 8]

It is known that the number of trees in a small forest will decrease by 55 % each year unless some new trees are planted. At the end of each year, 600600 new trees are planted to the forest. At the start of 20212021, there are 82008200 trees in the forest.

  1. Show that there will be roughly 90609060 trees in the forest at the start of 20262026. [4]

  2. Find the approximate number of trees in the forest at the start of 20412041. [4]

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Question 95

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hard

[Maximum mark: 13]

  1. The following diagram shows [PQ], with length 44 cm. The line is divided into an infinite number of line segments. The diagram shows the first four segments.

    2ecea1f156846207a208a3fc02a1af87be7132ca.svg

    The length of the line segments are mm cm, m2m^2 cm, m3m^3 cm, \dots, where 0<m<10 < m < 1.

    Show that m=45m = \dfrac{4}{5}. [5]

  2. The following diagram shows [RS], with length ll cm, where l>1l > 1. Squares with side lengths nn cm, n2n^2 cm, n3n^3 cm, \dots, where 0<n<10 < n < 1, are drawn along [RS]. This process is carried on indefinitely. The diagram shows the first four squares.

    282d818bda418427e2f4b47fb94d3fce3af0ad9c.svg

    The total sum of the areas of all the squares is 2511\dfrac{25}{11}. Find the value of ll. [8]

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Question 96

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hard

[Maximum mark: 14]

The first two terms of an infinite geometric sequence, in order, are

3log3x,2log3x,where x>0.3\log_3x,\,\, 2\log_3x,\,\, \text{where $x > 0$.}
  1. Find the common ratio, rr. [2]

  2. Show that the sum of the infinite sequence is 9log3x9\log_3 x. [3]

The first three terms of an arithmetic sequence, in order, are

log3x,log3x3,log3x9,where x>0.\log_3x,\,\, \log_3 \dfrac{x}{3},\,\, \log_3\dfrac{x}{9},\,\, \text{where $x > 0$.}
  1. Find the common difference dd, giving your answer as an integer. [3]

Let S6S_6 be the sum of the first 66 terms of the arithmetic sequence.

  1. Show that S6=6log3x15S_6 = 6\log_3 x - 15. [3]

  2. Given that S6S_6 is equal to one third of the sum of the infinite geometric
    sequence, find xx, giving your answer in the form apa^p where a,pZa,p \in \mathbb{Z}. [3]

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Question 97

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[Maximum mark: 7]

Consider the expansion of (2x6+x2q)10\bigg(2x^6+\dfrac{x^2}{q}\bigg)^{10},  q0q \neq 0. The coefficient of the term

in x40x^{40} is twelve times the coefficient of the term in x36x^{36}. Find qq.

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Question 98

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hard

[Maximum mark: 7]

Consider f(x)=logk(8x2x2)f(x) = \log_k(8x-2x^2), for 0<x<40 < x < 4, where k>0k > 0.

The equation f(x)=3f(x) = 3 has exactly one solution. Find the value of kk.

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Question 99

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hard

[Maximum mark: 15]

The first three terms of an infinite geometric sequence are k4,4,k+2k-4,\,\, 4,\,\, k+2, where kZk \in \mathbb{Z}.

    1. Write down an expression for the common ratio, rr.

    2. Hence show that kk satisfies the equation k22k24=0k^2 - 2k - 24 = 0.[5]

    1. Find the possible values for kk.

    2. Find the possible values for rr. [5]

  1. The geometric sequence has an infinite sum.

    1. Which value of rr leads to this sum. Justify your answer.

    2. Find the sum of the sequence. [5]

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Question 100

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hard

[Maximum mark: 14]

Alex and Julie each have a goal of saving $30000\$30\hspace{0.15em}000 to put towards a house deposit. They each have $16000\$16\hspace{0.15em}000 to invest.

  1. Alex chooses his local bank and invests his $16000\$16\hspace{0.15em}000 in a savings account that offers an interest rate of 5%5\% per annum compounded annually.

    1. Find the value of Alex's investment after 77 years, to the nearest hundred dollars.

    2. Alex reaches his goal after n years, where n is an integer. Determine the value of n. [4]

  2. Julie chooses a different bank and invests her $16000\$16\hspace{0.15em}000 in a savings account that offers an interest rate of r%r\% per annum compounded monthly, where rr is set to two decimal places.

    Find the minimum value of rr needed for Julie to reach her goal after 1010 years. [3]

  3. Xavier also wants to reach a savings goal of $30000\$30 \hspace{0.15em}000. He doesn't trust his local bank so he decides to put his money into a safety deposit box where it does not earn any interest. His system is to add more money into the safety deposit box each year. Each year he will add one third of the amount he added in the previous year.

    1. Show that Xavier will never reach his goal if his initial deposit into the safety deposit box is $16000\$16\hspace{0.15em}000.

    2. Find the amount Xavier needs to initially deposit in order to reach his goal after 77 years. Give your answer to the nearest dollar. [7]

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Question 101

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hard

[Maximum mark: 6]

Solve log3(sinx)log3(cosx)=1\log_{\sqrt{3}}(\sin x) - \log_{\sqrt{3}}(\cos x) = 1, for 0<x<π20 < x < \dfrac{\pi}{2}.

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Question 102

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[Maximum mark: 5]

In the expansion of x(2x+1)nx(2x + 1)^n, the coefficient of the term in x3x^3 is 20n20n, where nZ+n \in \mathbb{Z}^+. Find nn.

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Question 103

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[Maximum mark: 13]

Grant wants to save $40000\$40\hspace{0.15em}000 over 5 years to help his son pay for his college tuition. He deposits $20000\$20\hspace{0.15em}000 into a savings account that has an interest rate of 6%6\% per annum compounded monthly for 55 years.

  1. Show that Grant will not be able to reach his target. [2]

  2. Find the minimum amount, to the nearest dollar, that Grant would need to deposit initially for him to reach his target. [3]

Grant only has $20000\$20\hspace{0.15em}000 to invest, so he asks his sister, Caroline, to help him accelerate the saving process. Caroline is happy to help and offers to contribute part of her income each year. Her annual income is $37500\$37 \hspace{0.15em}500 per year. She starts by contributing one fifth of her annual income, and then decreases her contributions by half each year until the target is reached. Caroline's contributions do not yield any interest.

  1. Show that Grant and Caroline together can reach the target in 5 years. [4]

Grant and Caroline agree that Caroline should stop contributing once she contributes enough to complement the deficit of Grant's investment.

  1. Find the whole number of years after which Caroline will will stop contributing. [4]

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Question 104

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hard

[Maximum mark: 8]

Let f(x)=e3sin(πx4)f(x) = e^{3\sin \left(\frac{\pi x}{4}\right)}, for x>0x > 0.

The kkth maximum point on the graph of ff has xx-coordinate xkx_k, where kZ+k \in \mathbb{Z}^+.

  1. Given that xk+1=xk+dx_{k+1} = x_k + d, find dd. [4]

  2. Hence find the value of nn such that k=1nxk=992\displaystyle \sum_{k=1}^n x_k = 992. [4]

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Question 105

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[Maximum mark: 5]

In the expansion of (2x+1)n(2x + 1)^n, the coefficient of the term in x2x^2 is 40n40n, where nZ+n \in \mathbb{Z}^+. Find nn.

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Question 106

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hard

[Maximum mark: 7]

The sides of a square are 88 cm long. A new square is formed by joining the midpoints of the adjacent sides and two of the resulting triangles are shaded as shown. This process is repeated 55 more times to form the right hand diagram below.

AA640

  1. Find the total area of the shaded region in the right hand diagram above. [4]

  2. Find the total area of the shaded region if the process is repeated indefinitely.[3]

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Question 107

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hard

[Maximum mark: 5]

Solve the equation 154a=81a+215^{4a} = 81^{a+2} for aa. Express your answer in terms of ln3\ln 3 and ln5\ln 5.

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Question 108

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hard

[Maximum mark: 6]

  1. Write down and simplify the expansion of (3x)5(3-x)^5 in descending order of powers of xx. [3]

  2. Hence find the exact value of (2.9)5(2.9)^5. [3]

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Question 109

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hard

[Maximum mark: 6]

Given a sequence of integers, between 2020 and 300300, which are divisible by 99.

  1. Find their sum. [2]

  2. Express this sum using sigma notation. [2]

An arithmetic sequence has first term 500-500 and common difference of 88. The sum of the first nn terms of this sequence is negative.

  1. Find the greatest value of nn. [2]

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Question 110

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hard

[Maximum mark: 7]

Given that (5+nx)2(1+35x)n=25+100x+(5+nx)^2\bigg(1+\dfrac{3}{5}x\bigg)^n\hspace{-0.25em}=\hspace{0.05em}25+100x+\cdots, find the value of nn.

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Question 111

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[Maximum mark: 6]

A bouncy ball is dropped from a height of 22 metres onto a concrete floor. After hitting the floor, the ball rebounds back up to 8080 % of it's previous height, and this pattern continues on repeatedly, until coming to rest.

  1. Show that the total distance travelled by the ball until coming to rest can be expressed by

    2+4(0.8)+4(0.8)2+4(0.8)3+2 + 4(0.8) + 4(0.8)^2 + 4(0.8)^3 + \cdots[2]

  2. Find an expression for the total distance travelled by the ball, in terms of the number of bounces, nn. [2]

  3. Find the total distance travelled by the ball. [2]

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Question 112

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hard

[Maximum mark: 5]

Find the integer values of aa and bb for which

a+blog47+60log814=0.\begin{aligned} a + b\log_4 7 + 60\log_{8} 14 &= 0.\end{aligned}

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Question 113

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hard

[Maximum mark: 5]

Solve the equation 146x=64x+314^{6x} = 64^{x+3} for xx. Express your answer in terms of ln2\ln 2 and ln7\ln 7.

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Question 114

no calculator

hard

[Maximum mark: 8]

The first three terms of a geometric sequence are lnx9\ln x^9, lnx3\ln x^3, lnx\ln x, for x>0x > 0.

  1. Find the common ratio. [3]

  2. Solve k=133klnx=27\displaystyle \sum_{k=1}^\infty 3^{3-k}\ln x = 27. [5]

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Question 115

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hard

[Maximum mark: 8]

  1. Show that log23cos2x=log4(3cos2x)\log_2 \sqrt{3-\cos 2x} = \log_4 (3-\cos 2x). [3]

  2. Hence, or otherwise, solve log4(3sinx)+14=log23cos2x\log_4 (3\sin x) \hspace{0.15em}+\hspace{0.15em} \dfrac{1}{4} = \log_2 \sqrt{3-\cos 2x}, for 0<x<π20 \hspace{-0.05em}<\hspace{-0.05em} x \hspace{-0.05em}<\hspace{-0.05em}\dfrac{\pi}{2}.[5]

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Question 116

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hard

[Maximum mark: 8]

  1. Show that log16(cos2x+7)=log4cos2x+7\log_{16}(\cos 2x + 7) = \log_4 \sqrt{\cos 2x + 7}. [3]

  2. Hence, or otherwise, solve log4(10cosx)=log16(cos2x+7)\log_4(\sqrt{10}\cos x) = \log_{16}(\cos 2x + 7), for 0<x<π20 < x < \dfrac{\pi}{2}.[5]

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Question 117

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hard

[Maximum mark: 7]

Given that (1+x)3(1+px)4=1+qx+93x2++p4x7(1 + x)^3(1 + px)^4 = 1 + qx + 93x^2 + \dots + p^4x^7, find the possible values of pp and qq.

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Question 118

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hard

[Maximum mark: 7]

  1. Write down the quadratic expression 3x2+5x23x^2 + 5x - 2 in the form (axb)(x+c)(ax-b)(x+c).[2]

  2. Hence, or otherwise, find the coefficient of the term in x9x^9 in the expansion
    of (3x2+5x2)5(3x^2+5x-2)^5. [5]

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Question 119

no calculator

hard

[Maximum mark: 15]

The first two terms of an infinite geometric sequence are u1=20u_1 = 20 and u2=16sin2θu_2 = 16\sin^2 \theta, where 0<θ<2π\text{\(0 < \theta < 2\pi\)}, and θπ\theta \neq \pi.

    1. Find an expression for rr in terms of θ\theta.

    2. Find the possible values of rr. [5]

  1. Show that the sum of the infinite sequence is 1003+2cos2θ\dfrac{100}{3 + 2\cos 2\theta}. [4]

  2. Find the values of θ\theta which give the greatest value of the sum. [6]

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Question 120

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hard

[Maximum mark: 15]

Bill takes out a bank loan of $100000\$100\hspace{0.15em}000 to buy a premium electric car, at an annual interest rate of 5.495.49%. The interest is calculated at the end of each year and added to the amount outstanding.

  1. Find the amount of money Bill would owe the bank after 1010 years. Give your answer to the nearest dollar. [3]

To pay off the loan, Bill makes quarterly deposits of $P\$P at the end of every quarter in a savings account, paying a nominal annual interest rate of 3.23.2%. He makes his first deposit at the end of the first quarter after taking out the loan.

  1. Show that the total value of Bill's savings after 1010 years is P[1.0084011.0081]P\bigg[\dfrac{1.008^{40}-1}{1.008-1}\bigg]. [3]

  2. Given that Bill's aim is to own the electric car after 1010 years, find the value for PP to the nearest dollar. [3]

Melinda visits a different bank and makes a single deposit of $Q\$\hspace{0.05em}Q, the annual interest\text{interest} rate being 3.53.5%.

    1. Melinda wishes to withdraw $8000\$8000 at the end of each year for a period of nn years. Show that an expression for the minimum value of QQ is

      80001.035+80001.0352+80001.0353++80001.035n.\dfrac{8000}{1.035} + \dfrac{8000}{1.035^2} + \dfrac{8000}{1.035^3} + \cdots + \dfrac{8000}{1.035^n}.
    2. Hence, or otherwise, find the minimum value of QQ that would permit Melinda to withdraw annual amounts of $8000\$8000 indefinitely. Give your answer to the nearest dollar. [6]

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The IB Math Analysis and Approaches (AA) SL Questionbank is a comprehensive set of IB Mathematics exam style questions, categorised into syllabus topic and concept, and sorted by difficulty of question. The bank of exam style questions are accompanied by high quality step-by-step markschemes and video tutorials, taught by experienced IB Mathematics teachers. The IB Mathematics AA SL Question bank is the perfect exam revision resource for IB students looking to practice IB Math exam style questions in a particular topic or concept in their AA Standard Level course.

The AA SL Questionbank is designed to help IB students practice AA SL exam style questions in a specific topic or concept. Therefore, a good place to start is by identifying a concept that you would like to practice and improve in and go to that area of the AA SL Question bank. For example, if you want to practice AA SL exam style questions that have Exponents & Logarithms in them, you can go to AA SL Topic 1 (Number & Algebra) and go to the Exponents & Logarithms area of the question bank. On this page there is a carefully designed set of IB Math AA SL exam style questions, progressing in order of difficulty from easiest to hardest. If you’re just getting started with your revision, you could start at the top of the page with Question 1, or if you already have some confidence, you could start at the medium difficulty questions and progress down.

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With an extensive and growing library of full length IB Math Analysis and Approaches (AA) SL exam style questions in the AA SL Question bank, finishing all of the questions would be a fantastic effort, and you will be in a great position for your final exams. If you were able to complete all the questions in the AA SL Question bank, then a popular option would be to go to the AA SL Practice Exams section on Revision Village and test yourself with the Mock Exam Papers, to simulate the length and difficulty of an actual IB Mathematics AA SL exam.